In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.
2 answers:
Answer:
3.1066≈3.1 feet
Step-by-step explanation:
3.1066≈3.1 feet
Answer:
3.1
Step-by-step explanation:
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