1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sladkih [1.3K]
3 years ago
15

1. Solve for x x + 1 = 6

Mathematics
2 answers:
mixer [17]3 years ago
7 0

Answer:

5

Step-by-step explanation:

Plz mark brainliest

Verdich [7]3 years ago
4 0

Answer:

5

Step-by-step explanation:

You might be interested in
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
Write the expression as either the sine, cosine, or tangent of a single angle.
Gnesinka [82]
Note that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y).

Therefore by setting x = π/2 and y = π/7, obtain
sin(π/2 + π/7) = sin(π/2)*cos(π/7) + cos(π/2)*sin(π/7)

The right side is what we want to evaluate.  It is equal to
sin(π/2 + π/7) = sin (9/14)π

Answer:  sin( \frac{9 \pi }{14})
6 0
3 years ago
HELP I'M DESPERATE I WILL MARK BRAINLIEST AND GIVE 30 POINTS
polet [3.4K]

Answer:

You could expect a 73.53.

3 0
3 years ago
Read 2 more answers
Find the indicated area under the standard normal curve.
polet [3.4K]

Answer:

0.1190

Step-by-step explanation:

If z = -1.18, the total area to the left under the standard normal curve is taken from the z-distribution table attached;

P(z < - 1.18) = 0.1190

Also, to the right of z = 1.18, we have;

P(z > 1.18) = 1 - P(z < 1.18)

From the second image attached from z-table, we have;

P(z > 1.18) = 1 - 0.8810

P(z > 1.18) = 0.1190

Thus, the total area to the left of z= - 1.18 and to the right of z= 1.18 under the standard normal curve is 0.1190

8 0
3 years ago
Simplify, please ;-;
Nezavi [6.7K]

Answer:

2x+3-1

Step-by-step explanation:

hope this helps :)

6 0
3 years ago
Other questions:
  • Scientists specializing in nutrition conduct studies that provide us with the information we need to make healthy
    12·2 answers
  • Identify two composite numbers that each have 8 as a factor
    10·1 answer
  • What is the value of 5^3i^9?
    5·1 answer
  • Please help.. will mark brainlyiest
    14·1 answer
  • A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second 2 . What is the
    6·1 answer
  • If n is even, which of the following cannot be odd?
    6·1 answer
  • Arionna claims that since there are 3 feet in a yard there are 9 cubic feet in a cubic yard
    9·2 answers
  • Please answer... I appreciate it​
    15·1 answer
  • -3.6≥-0.3a+12 <br> help please i will mark brainliest
    6·1 answer
  • Name of devices is used for drawing curves which can't be drawn by a compass<br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!