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3 years ago

Could anybody answer this

Mathematics

1 answer:

Alexandra [31]3 years ago

5 0

Try this solution:

1. if to transform the given equation into the standard form:

x²+y²-4x+6y-3=0;

(x²-4x+4)+(y²+6y+9)-16=0;

(x-2)²+(y+3)²=4²

2. Using the standard form it is possible to find the coordinates of the centre of given circle: x=2; y= -3

answer: b) - (2;-3)

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ivanzaharov [21]

Answer:

1. 4

2. 16

3. 4/3

4. 64/3

Step-by-step explanation:

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3 years ago

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snow_lady [41]

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3 years ago

Is number 4 right please

Flura [38]

Yes it is indeed correct

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3 years ago

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antoniya [11.8K]

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3 years ago

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Help! I have looked at so many lessons on writing exponential functions from a graph and nothing has helped.

Over [174]

Answer:

y = $8(-\frac{1}{2})^x$

Step-by-step explanation:

Let the equation of the exponential function is,

y = a(b)ˣ

Since the graph of this function passes through two points $(4, \frac{1}{2})$ and (3, -1)

For the point $(4, \frac{1}{2})$ ,

$\frac{1}{2}=a(b)^4$ ---------(1)

For second point (3, -1),

-1 = a(b)³ ---------(2)

Divide equation (2) by equation (1),

$\frac{\frac{1}{2}}{-1}$ = $\frac{a(b)^4}{a(b)^3}$

$-\frac{1}{2}=b^{(4-3)}$

$-\frac{1}{2}=b$

From equation (2)

-1 = $a(-\frac{1}{2})^3$

-1 = $-\frac{1}{8}a$

a = 8

Therefore, equation of the exponential function will be,

y = $8(-\frac{1}{2})^x$

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3 years ago