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BartSMP [9]
3 years ago
5

In the diagram below what is the intersection on lines l and m?

Mathematics
2 answers:
QveST [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Lines M and L intersect at point B

alexgriva [62]3 years ago
3 0
It is B

Just trust me mate
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darryl spent $276 on books. math books cost $21 and English books cost $30. if he bought a total of 11 books how many of each ki
nata0808 [166]
6 math books would be 126
5 English books would be 150
126+150=276 
6 0
4 years ago
What is the equation of the line that passes through the point (1,5) and it parallel to the line 2x + y = 10?
Ivan
Make the equation into slope intercept form: y = mx + b
2x + y = 10
Subtract 2x
y = -2x + 10
Parallel means same slope
Y = -2x + b
Plug in the point (1,5)
5 = -2(1) + b, b = 7
Solution: y = -2x + 7
5 0
3 years ago
Read 2 more answers
Simplify ¬(m∧(w∨¬m)) to ¬m∨¬w
kirill [66]

Answer:

m

Step-by-step explanation:

•{mm~∆∆¶¶))7)(´;д;`)

7 0
4 years ago
A square section of a kitchen floor is made of
Ronch [10]

Answer:

I found the answer to this question by finding the square root of 49 because the section is a square. The square root of 49 is 7, so there are 7 tiles on each side of the floor.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
12 2/3 ^ 2 1/3what is 12 2/3 divided by 2 1/3 ​
Semmy [17]

Answer:

(12 2/3)/( 2 1/3)= 38/7 or 5 3/7 or 5.43 decimal

Step-by-step explanation:

Simplify the following:

(12 + 2/3)/(2 + 1/3)

Put 2 + 1/3 over the common denominator 3. 2 + 1/3 = (3×2)/3 + 1/3:

(12 + 2/3)/((3×2)/3 + 1/3)

3×2 = 6:

(12 + 2/3)/(6/3 + 1/3)

6/3 + 1/3 = (6 + 1)/3:

(12 + 2/3)/((6 + 1)/3)

6 + 1 = 7:

(12 + 2/3)/(7/3)

Put 12 + 2/3 over the common denominator 3. 12 + 2/3 = (3×12)/3 + 2/3:

((3×12)/3 + 2/3)/(7/3)

3×12 = 36:

(36/3 + 2/3)/(7/3)

36/3 + 2/3 = (36 + 2)/3:

((36 + 2)/3)/(7/3)

36 + 2 = 38:

(38/3)/(7/3)

Multiply the numerator by the reciprocal of the denominator, (38/3)/(7/3) = 38/3×3/7:

(38×3)/(3×7)

(38×3)/(3×7) = 3/3×38/7 = 38/7:

Answer:  38/7

8 0
3 years ago
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