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mojhsa [17]
2 years ago
8

The width of a rectangle is 6n - 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
6 0

I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

Answer:  Perimeter =  5 + 12n + 11 feet ; Perimeter =  17n+ 11 feet

Step-by-step explanation:

Using Length = 2.5+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5 + 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5 + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5 + 16feet + 12n - 5feet

Perimeter =  5 + 12n + 11 feet

Using Length = 2.5n+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5n+ 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5n + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5n + 16feet + 12n - 5feet

Perimeter =  5n + 12n + 11 feet

Perimeter =  17n+ 11 feet

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