Question

Hi! Please help me, will mark brainliest!

Answer 1

Answer:

p(t) = 0 for t = 1

p(t) = 1 for t = 1/8 = 8^-1

Step-by-step explanation:

the graph you will have to do yourself.

just go there and type in

$- log_{8}(x)$

well, don't type "log" in letters.

you start by typing the "-" sign, and then you need to look up the functions by clicking on the "funcs" button and look for the log functions .

pick the

$log_{a}$

option. and then simply enter 8 as the first parameter in the {} brackets and x as the second in the () brackets.

and then you see.

any logarithm is 0 for x (or t) = 1.

because any a⁰ = 1.

and the logarithm gives you that exponent of the base number that leads to the given x value.

in other words : a logarithm is the inverse function of an exponential function.

the exponential function is

y = a^x

and the logarithm then determines

$x = log_{a}(y)$

that is all.

and

$- log_{8}(x) = 1$

means that the logarithm itself delivered -1.

and 8^-1 = 1/8

so, p(t) = 1 for t = 1/8