Answer:

Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

Solve for <em>r: </em>
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Simplify. Thus:

Finally, add:

We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:

If two secants intersect from a point outside of the circle, then the product of the lengths of the secant and its external segment equals the product of the other secant and its external segment.
#1
5(x+5) = 6(4+6)
5x + 25 = 6 * 10
5x = 60 - 25
5x = 35
x = 7
#2
4(x+4) = 3(5+3)
4x + 16 = 3 * 8
4x = 24 - 16
4x = 8
x = 8/4
x = 2
Answer:
10
There are 16 blocks that are painted with 2 colors which are red and blue and 1 block that isn't painted
27-17 = 1
X=<span><span><span>43</span>y</span>+<span><span>−4</span><span>3 hope this helped</span></span></span>