If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Given that the sum of an integer and 7 more than the next consecutive integer is 66.
Integer is a number that is written without a fraction component. It can be positive as well as negative.
let the first integer be x.
Consecutive integer will be x+1.
Sum of integer and 7 more than the next consecutive integer is 66.
Sum according to the given information=x+x+1+7
=2x+8
2x+8=66
2x=66-8
2x=58
x=58/2
x=29
Next integer=29+1-30.
Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Learn more about integers at brainly.com/question/17695139
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Answer:
See below.
Step-by-step explanation:
1. 3 * 15 + 4 * 15 - 5 * 15
45 + 60 - 75
105 - 75
30
2. 3x + 4x - 5x
7x - 5x
2x
3. 3(x-2) + 4(x-2) - 5(x-2)
3x - 6 + 4x - 8 - 5x + 10
2x - 4
4. (I'm not typing that out)
7.5x + 19.5 + 10x + 26 - 12.5x - 32.5
5x+13
-hope it helps
Answer:
1/4
Step-by-step explanation:
4 classes, each class gets one spot!
Answer:
y = 4000/x²
Step-by-step explanation:
The volume of the building is expressed as;
V = x²y where;
x is the length and width of the base.
y is the height of the building
Given
Volume V = 4000m³
Substitute the given volume into the equation as shown;
4000 = x²y
Make y the subject of the formula by dividing both sides by x²
4000/x² = x²y/x²
4000/x² = y
Rearrange
y = 4000/x²
Hence equation for y, the height of the building, in terms of x, the length and width of the base is expressed as y = 4000/x²
