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AVprozaik [17]
3 years ago
6

Rita is starting a running program. The table shows the total number of miles she runs in different weeks. What is the equation

of the line of best fit for the data? State each number to the thousandths place.
Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:Y≈ 1.671 x + 4.699

Step-by-step explanation:

ASHA 777 [7]3 years ago
3 0

Step-by-step explanation:

Y = 1.671 X + 4.699

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a water sprinkler sends water out in a circular pattern. determine how large an area is watered. the radius of watering is 18ft.
Sergeeva-Olga [200]
Use the formula for area of a circle,
a = \pi \times {r}^{2}
and they give an approximation so use that for pi
5 0
3 years ago
I have dyscalculia and I hate math. I am absolutely confused about multi step equations with fractions.
Galina-37 [17]

Answer:

If you have *dyslexia, then how do you know how to spell so well?

Step-by-step explanation:

7 0
2 years ago
What is the LCM how do I find it
Nimfa-mama [501]

One of the quickest ways to find the LCM of two numbers is to use the prime factorization of each number and then the product of the least powers of the common prime factors will be the LCM of those numbers.

LCM-LOWEST COMMON MULTIPLE

6 0
3 years ago
Use the Alternating Series Approximation Theorem to find the sum of the series sigma^infinity_n = 1 (-1)^n - 1/n! with less than
DanielleElmas [232]

Answer:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198 -0.0000248

For the 7th term we have 3 decimals of approximation but our value is 0.000198 higher than the error required, so we can use the 8th term and we have that |-0.0000248|= 0.0000248 and with this we have 4 decimals of approximation so if we add the first 8 terms we have a good approximation for the series with an error bound lower than 0.0001.

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198-0.0000248 =0.632118

Step-by-step explanation:

Assuming the following series:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!}

We want to approximate the value for the series with less than 0.0001 of error.

First we need to ensure that the series converges. If we have a series \sum a_n where a_n = (-1)^n b_n [/tex] or a_n =(-1)^{n-1} b_n where b_n \geq 0 for all n if we satisfy the two conditions given:

1) lim_{n \to \infty} b_n =0

2) {b_n} is a decreasing sequence

Then \sum a_n is convergent. For this case we have that:

lim_{n \to \infty} \frac{1}{n!} =0

And \frac{1}{n!} because \frac{1}{n!} =\frac{1}{n (n-1)!} and \frac{1}{n(n-1)!} < \frac{1}{(n-1)!}

So then we satisfy both conditions and then the series converges. Now in order to find the approximation with the error required we can write the first terms for the series like this:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198 -0.0000248

For the 7th term we have 3 decimals of approximation but our value is 0.000198 higher than the error required, so we can use the 8th term and we have that |-0.0000248|= 0.0000248 and with this we have 4 decimals of approximation so if we add the first 8 terms we have a good approximation for the series with an error bound lower than 0.0001.

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198-0.0000248 =0.632118

6 0
4 years ago
8 blocks can build a house. Jimmy has 165 blocks, how many houses can he build? How many blocks will he have left?​
noname [10]

Answer:

He can build 20 houses. He will have 5 left over.

Step-by-step explanation:

8 x 20 = 160

165 (total blocks) - 160 (highest possibility) = 5 (not enough to build a house, which is why they are left over)

3 0
4 years ago
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