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Inessa05 [86]
3 years ago
8

I need help with question A. Y= what????

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

maybe 2

Step-by-step explanation:

im not really sure

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PLEASE HELP:
Tema [17]
X=moira y=mother

x=1/2y-3 

x=1/2(76)-3

x=38-3

x=35  

Moira is 35 years old.
3 0
3 years ago
Factorization of 4x+7-x
klemol [59]

Answer:

3x+7

Step-by-step explanation:

4x+7-x=4x-x+7=3x+7

8 0
3 years ago
Find y and x values please
Aleonysh [2.5K]
(-2,6) iissssssss the answer
3 0
4 years ago
I just need some help solving this question, i’m not sure what to do
KonstantinChe [14]

From the double-angle identity,

cos2x=2*sinx*cosx

we can rewritte our given equation as:

4sinxcosx-2cosx=0

By factoring 2cosx on the left hand side, we have

2cosx(2sinx-1)=0

This equation has 2 solutions when

\begin{gathered} cosx=0\text{ ...\lparen A\rparen} \\ and \\ 2sinx-1=0\text{ ...\lparen B\rparen} \end{gathered}

From equation (A), we obtain

x=\frac{\pi}{2}\text{ or }\frac{3\pi}{2}

and from equation (B), we have

\begin{gathered} sinx=\frac{1}{2} \\ which\text{ gives} \\ x=\frac{\pi}{6}\text{ or }\frac{5\pi}{6} \end{gathered}

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

\begin{gathered} 2ccos(2\times0)-2cos0=0 \\ which\text{ gives} \\ 2\times1-2\times1=0 \\ so\text{ 0=0} \end{gathered}

then, x=0 is another solution. In summary, we have obtained the following solutions:

\begin{gathered} x=0 \\ x=\frac{\pi}{2}\text{or}\frac{3\pi}{2}\text{ and } \\ x=\frac{\pi}{6}\text{or}\frac{5\pi}{6} \end{gathered}

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:

Therefore, the solution set is: {0}

7 0
1 year ago
11. A spinner is divided into 12 equal sections. Five of the sections are labeled with
Licemer1 [7]

Answer:

Probability of spinning an odd number = 1/3

Step-by-step explanation:

4 odd out of 12 sections

Probability of spinning an odd number = 4/12 = 1/3

7 0
3 years ago
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