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3 years ago

10 meters = ______________ feet

Mathematics

1 answer:

Leni [432]3 years ago

5 0

Answer:

brainliest?

Step-by-step explanation:

10meters=32,8084 feet

16gallons= 60566592 mm³

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Is 243 prime??????????

Fofino [41]

No, 243 is not a prime number, it is a composite number.

I hope I helped you again :-)

5 0

4 years ago

Read 2 more answers

In the figure below, find the length of AD. Round your answer to the nearest tenth.

goldenfox [79]

Answer:

12.4

Step-by-step explanation:

First you need to find the hypotenuse of the other triangle, because it makes up a necessary side for finding AD. Pythagorean theorem states that

a^2 + b^2 = c^2 where a and b are leg lengths and c is the hypotenuse. For the triangle on the left, you're given 2 legs. So you can substitute those into that formula:

a^2 + b^2 = c^2

(10)^2 + (6)^2 = c^2

100 + 36 = c^2

136 = c^2.

Now take the square root of both sides to isolate c.

11.6619038 = c.

11.6619038 rounds to 11.7 so c = 11.7

Now that you have the second leg length for the triangle on the right, you can find its hypotenuse.

Follow the same process. Substitute your values into the equation and then solve for c:

a^2 + b^2 = c^2

(11.7)^2 + (4)^2 = c^2

136.89 + 16 = c^2

152.89 = c^2

Now find the square root of both sides to isolate c

12.3648696 = c.

12.3648696 rounds to 12.4 so c = 12.4

So the distance of AD is 12.4

4 0

3 years ago

There is a book sale at the libaray the price for each book is $4 which expression can be used to show how much money the librar

ASHA 777 [7]

4 x 289= the total cost

6 0

3 years ago

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

Drupady [299]

Answer:

$V = \frac{\pi^2}{8}$

$V = 1.23245$

Step-by-step explanation:

Given

$y = \cos 2x$

$y = 0; x = 0; x = \frac{\pi}{4}$

Required

Determine the volume of the solid generated

Using the disk method approach, we have:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {(\cos 2x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

Apply the following half angle trigonometry identity;

$\cos^2(x) = \frac{1}{2}[1 + \cos(2x)]$

So, we have:

$\cos^2(2x) = \frac{1}{2}[1 + \cos(2*2x)]$

$\cos^2(2x) = \frac{1}{2}[1 + \cos(4x)]$

Open bracket

$\cos^2(2x) = \frac{1}{2} + \frac{1}{2}\cos(4x)$

So, we have:

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {[\frac{1}{2} + \frac{1}{2}\cos(4x)]} \, dx$

Integrate

$V = \pi [\frac{x}{2} + \frac{1}{8}\sin(4x)]\limits^{\frac{\pi}{4}}_0$

Expand

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [\frac{0}{2} + \frac{1}{8}\sin(4*0)])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [0 + 0])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})])$

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}\sin(\pi)])$

$\sin \pi = 0$

So:

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}*0])$

$V = \pi *[{\frac{\pi}{8}]$

$V = \frac{\pi^2}{8}$

$V = \frac{3.14^2}{8}$

$V = 1.23245$

4 0

3 years ago

Each whole number from 0 to 9 is paired with its opposite. is this a function or not

dimaraw [331]

A function has the property that each element of the domain maps to only one element. For example, if there's ever the case where a relation includes point (1,2) and (1,3) then that relation is not a function. So for each case write down all the points as described. If one point in the domain ever maps to two different points, then it's not a function

8 0

3 years ago