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3 years ago

A number x is rounded to 20 significant figures is 1300 write down the error interval for x

Mathematics

1 answer:

Andrej [43]3 years ago

8 0

Answer:

i know it something like x=5 or something

Step-by-step explanation:

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If ∠A and ∠B are complementary, find the value of x given that ∠A=3x-2 and ∠B=x+12

xxMikexx [17]

Answer:

x=20 degrees

Step-by-step explanation:

complementary means the angles equal 90 degrees

so ∠A+∠B=90 degrees

∠A=3x-2 and ∠B=x+12

so subsitute

(3x-2)+(x+12)=90

then solve for x

4x+10=90

4x=80

x=20 degrees is your answer

6 0

3 years ago

Can a system of two linear equations have only two or three solutions? Why or why not?

alexira [117]

Answer:A system of linear equations usually has a single solution, but sometimes it can have no solution, or infinite solutions.One solution. A system of linear equations has one solution when the graphs intersect at a point.

Step-by-step explanation:

6 0

3 years ago

Please help me ASAP explain for brainlist.

Verdich [7]

Answer:

assuming that there are an equal number of colored marbles in the bag and their total is 20 marbles in the bag:

C) 17/20

Step-by-step explanation:

6 0

3 years ago

What percent of a present amount of radioactive radium (226Ra) will remain after 1200 years? The half life of 226Ra is 1599 year

sp2606 [1]

Answer:

59.44%

Step-by-step explanation:

$M_{R} = \frac{M_{O} }{2^{n} }$

$n=\frac{t}{t\frac{1}{2} }$

Where $M_{R}$ = mass remaining

$M_{O}$ =original mass.

t= time

$t\frac{1}{2}$ =half life

$t\frac{1}{2}$ =1599, t= 1200, $M_{O}$ =226, $M_{R}$ =?

$n=\frac{1200}{1599}$

n= 0.750469

$M_{R} = \frac{226}{2^{ 0.750469} }$

$M_{R}$ =134.3367amu

percentage of mass remaining = $\frac{134.3367amu}{226amu}$ *100%

= 59.44%

8 0

3 years ago

What’s the answer to this question below. A b c or d

maks197457 [2]

Answer:

$a=0$

Step-by-step explanation:

The given expression is;

$(\frac{1}{7})^{3a+3} =343^{a-1}$

This implies that;

$7^{-1(3a+3)} =7^{3(a-1)}$

Equate the exponents;

$-1(3a+3) =3(a-1)$

Expand;

$-3a-3 =3a-3$

$-3a-3a =-3+3$

$-6a=0$

$a=0$

7 0

3 years ago

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