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ololo11 [35]
3 years ago
8

Mary used the equation x = $4 * y to represent the table above. What mistake did she make, and what should the correct equation

be to represent this table?

Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
Mary removed the dollar sign from (X.)
We know this because $4.00x$5.00=$20.00 so that’s correct and we know that $12.50x $4.00=$50.00. So, our only error here is that there is no dollar sign in our (X) numbers. So that is Mary’s mistake. We can correct it by simply adding a dollar sign to 20 to make $20.00 and adding another dollar sign to 50 to make $50.00

Hope this helps!
ollegr [7]3 years ago
5 0

Answer:  she has to remove the $ sign from the equation

Step-by-step explanation:

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Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

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For C=5.50\ m

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substitute and solve for r

5.50=2(3.14)r

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For C=7.85\ m

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substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

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substitute

SA=4(3.14)(0.88)^{2}

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<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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