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Vladimir [108]
4 years ago
11

Please help me, solve for y 2x-y=5

Mathematics
1 answer:
Novosadov [1.4K]4 years ago
3 0
<span><span><span>2x</span>−y</span>=5

</span>Add -2x to both sides.

<span><span><span><span>2x</span>−y</span>+<span>−<span>2x</span></span></span>=<span>5+<span>−<span>2x

</span></span></span></span><span><span>−y</span>=<span><span>−<span>2x</span></span>+5

</span></span>Divide both sides by -1.<span><span><span><span><span>
</span></span></span></span></span><span><span>
\frac{-y}{-1} =  \frac{-2x+5}{-1}
‌</span></span><span>y=<span><span>2x</span>−5

</span></span>Answer:

<span>y=<span><span>2x</span>−<span>5</span></span></span>
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a triangle has side lengths of 13, 15, and 17. determine whether the triangle is right, acute, or obtuse.
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3 years ago
Rewrite the fraction without an exponent (7/8)^-2
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64/49 or 1 and 15/49

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2. Solve and simplify

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4 years ago
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3 years ago
What is one of the solutions to the following system of equations?
Amanda [17]

Answer:

(8,-1)

Step-by-step explanation:

Given :   x^{2} +y^{2} =65

               x+y=7

To Find: solution of given system of equations.

Solution:

Equation a :   x^{2} +y^{2} =65

Equation b :  x+y=7

Substitute the value of y from equation b in equation a

y from equation b : y = 7-x

Now substitute value of y in equation a

Thus equation a becomes:

 x^{2} +(7-x)^{2} =65

x^{2} +49+x^{2}-14x =65

2x^{2} -14x =65-49

x^{2} -7x -8=0

x^{2} -8x+x -8=0

x(x-8)+1(x-8)=0

(x+1)(x-8)=0

⇒ x= -1 and x = 8

Now substitute values of x  in equation b to obtains values of y

⇒ x+y=7

for x = -1

⇒ -1+y=7

⇒ y=7+1

⇒ y=8

Thus (x,y)=(-1,8)

For x =8

⇒ 8+y=7

⇒ y=7-8

⇒ y=-1

Thus (x,y)=(8,-1)

Hence Option A is the correct solution .


6 0
4 years ago
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