Answer: side ways
Step-by-step explanation:
9514 1404 393
Answer:
4 1 5 3 6 2
Step-by-step explanation:
The general approach to this proof is to show the triangles created by the diagonal are congruent. Then, parts of those triangles (opposite sides) are congruent. The congruence of the triangles is shown by making use of the fact that alternate interior angles are congruent, and the diagonal is congruent to itself. Thus, you have two angles and the side between shown as congruent, and can invoke the ASA postulate.
The steps of the proof (1 to 6) are already in order. The task is to find the geometric relation the step is describing from the list on the left.
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Statements A to F on the left match with numbered statements 1 to 6 on the right as follows:
A - 4 (reflexive prop)
B - 1 (given)
C - 5 (ASA)
D - 3 (alt int angle)
E - 6 (the end point of the proof)
F - 2 (definition)
Answer:
B. take up less space than when the data set is not organized
Step-by-step explanation:
Well, in this question, you can analyze one answer after the other.
In A see important values in the data set, this makes sense when determining mode and median of a data set.Median is the center value in a data set, while mode is the repeated value in the set.When data set is arranged from smallest to the largest, the median and mode can be seen clearly.These can be the important values in the data set
In C. More easily see the maximum and minimum values in the data set, is possible especially when data is arranged in an increasing order.The smallest value will start, where as the largest value will be at the end.This applies to D too.
However in B, it will depend with the manner you would like to analyze the data.For example organizing data using tables will make your data easy to understand and present your analysis.Another person will group the data in intervals to identify the frequency of in data set.So, you see, its not about space taken by data but how you would like to present your data when analyzing it.
Hope this helps.
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is
