A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7 
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB = = 
= 5
DE = 
= 
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
Answer:
Trying to solve this leads to an absurdity, so No Solution.
Step-by-step explanation:
5x+12=5x−7
Lets attempt to solve:
Subtract 5x from both sides
5x - 5x + 12 = 5x - 5x - 7
0 + 12 = 0 - 7
12 = -7
This is absurd so there is no solution.
(2x^2 + 4x + 6) - (-3x - 5x^2 + 4)
The negative sign separating the expressions is just multiplying the rightmost expression by -1.
(2x^2 + 4x + 6) + (3x + 5x^2 - 4)
Now, let's add together terms that share the same variable.
2x^2 + 5x^2 = 7x^2
4x + 3x = 7x
6 + (-4) = 2
Let's combine each of these terms into one expression.
7x^2 + 7x + 2 is the final answer.
