See photos for solutions and steps :)
Answer:
6 months, i used the equation from part a so i know it’s right
Step-by-step explanation:
a) 15 + 12x = 87
b) 12x = 87-15=72
72/12 = 6
Answer:
The equation for a is 
The altitute is 101,428.57 feet
Step-by-step explanation:
You know that the relationship between ground temperature and atmospheric temperature can be described by the formula
t = -0.0035a +g
where:
- t is the atmospheric temperature in degrees Fahrenheit
- a is the altitude, in feet, at which the atmospheric temperature is measured
- g is the ground temperature in degrees Fahrenheit.
Solving the equation for a:
-0.0035a +g=t
-0.0035a= t - g


<u><em>The equation for a is </em></u>
<u><em></em></u>
If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F
Replacing in the equation for a you get:


a= 101,428.57
<u><em>The altitute is 101,428.57 feet</em></u>
Answer:
The answer is b
Step-by-step explanation:
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.