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2 years ago

ANSWER ASAP PLEASEEE

Mathematics

1 answer:

irga5000 [103]2 years ago

3 0

Answer:

x = 20°

Step-by-step explanation:

Since BD = CD then Δ BCD is isosceles and its base angles are congruent, so

∠ CBD = ∠ BCD = 80° , then

∠ BDC = 180° - (80 + 80)° = 180° - 160° = 20°

∠ ADC = 180° - (80 + 60)° ← sum of angles in triangle

∠ ADC = 180° - 140° = 40° , then

∠ BDC + x = 40°

20° + x = 40° ( subtract 20° from both sides )

x = 20°

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Step-by-step explanation:

x = -2 and x = -5

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3 years ago

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3 years ago

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3 years ago

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3 years ago

You and your friend mix water and cirtic acid. You add 3 cups of citrtic acid for every 16 cups of water Your friend adds 2 cups

Vlad [161]

Answer:

A's mixture is more acidic.

Step-by-step explanation:

Given:

Two friends mix water and citric acid.

One (Let A) add 3 cups of citric acid for every 16 cups of water and another (Let B)adds 2 cups of citric acid for every 12 cups of water.

Now, we have to find that whose mixture is more acidic means:-

Solution:

A add 3 cups of citric acid for every 16 cups of water, the ratio = $\frac{3}{16}$

B adds 2 cups of citric acid for every 12 cups of water = $\frac{2}{12}$

Now, to find that who mix more citric acid in the mixture, firstly we will equalize the denominator of both fraction by taking LCM so that can be compare easily.

LCM of 16 and 12:- 48

16 - 16, 32, 48, 64, 80, 96....

12 - 12, 24, 36, 48, 60, 72.......

For friend A - $\frac{3\times3}{16\times3} =\frac{9}{48}$

For friend B - $\frac{2\times4}{12\times4} =\frac{8}{48}$

We found that in terms of 48 cups of water, friend A mixes 9 cups of acid while friend B mixes 8 cups of acid, means A is adding more acid than B and hence friend A's mixture is more acidic.

4 0

3 years ago