Answer:
The maximum height of soccer ball is 12.25 ft.
Step-by-step explanation:
It is given that Tiffany kicks a soccer ball off the ground and in the air, with an initial velocity of 28 feet per second. It means v = 28 ft.
Given formula is
The initial height of ball is 0.
The height of ball defined by the function
It is a downward parabola and the vertex of a downward parabola is the point of maxima.
The vertex of a parabola 
is
Therefore the maximum height of soccer ball is 12.25 ft.
10+45+16
The answer would be 71
<u>The graph shown is the second derivative</u>
⇒ first derivative equals the area between
- the second derivative function from 0 to 2
- the axis
<u>Thus the first derivative f(2) equals</u> 
- c: represents the initial position
<u>However there is an inital position for the first derivative</u> ⇒ f(0) = 2.5
<u>Therefore we must add the initial position to the first derivative found</u>
<u>f(2) = 8 + 2.5 = 10.5</u>
Hope that helps!
$8 + $7 + $13 + 15 = $43
$x - $43 = $12
x = $55
i am a mathematics teacher. if anything to ask please pm me
