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2 years ago

PLEASE HELP!! 20 POINTS PLUS BRAINLIEST IF YOURE RIGHT!!

1 answer:

8 0

Firstly, we have to find the mean. The mean is simply the average of the numbers, which we find by adding each number in the sequence and then dividing that result by the total amount of numbers.

13.3 + 14.3 + 15.3 + 16.3 + 17.3 = 76.5

76.5 / 5 = 15.3

Okay, so our average is 15.3.

Now, we have to subtract the mean from each number and then square the result.

(13.3 - 15.3)^2 = 4
(14.3 - 15.3)^2 = 1
(15.3 - 15.3)^2 = 0
(16.3 - 15.3)^2 = 1
(17.3 - 15.3)^2 = 4

Now we have to find the mean of those numbers!

4 + 1 + 0 + 1 + 4 = 10

10 / 2 = 2

Finally, we take the square root of that number and we have our standard deviation. =)

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Juan rolls a 6-sided number cube 4 times. each time, the result is 2. which best describes the events? dependent: each outcome w

scoray [572]

Answer: 1/6

because there are 6 side to a cube and you can only have a outcome of 1 so therefore, the answer is 1/6

7 0

1 year ago

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago

June 1st = 1223 starting balance

Dima020 [189]

Answer:

The average daily balance for the month of June is 55.16

Solution:

Given, June 1st = 1223 starting balance

June 10th = 615 deposit

So these will add in the account

June 15th = withdrawal of -63

June 22nd = withdrawal of -120

These will be subtracted from the account.

$\therefore$ We have to add the deposits and subtract the withdrawals from the starting balance to obtain the total amount.

So, the total amount deposited in June is (1223 +615-63-120) = 1655

The total days in June is 30. In 30 days, the total deposit is 1655. To calculate the average balance, we have to divide the total amount by the total number of days in the month.

So, in 1 day the deposit is $\frac{1655}{30} = 55.16$

Hence, the average daily balance for June is = 55.16

5 0

2 years ago

Wholelotta swag aneways

aksik [14]

Answer:

period.

Step-by-step explanation:

3 0

2 years ago

Can someone help me please ?

Oliga [24]

I think that it might be "c" but I am not sure but hey it is worth a shot sorry if I am wrong!

7 0

3 years ago