Using the distance formula;
![|d|=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%7Cd%7C%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
From the points given:
x₁=-1 y₁=-2 x₂=8 y₂=10
substitute the values into the formula;
![|d|=\sqrt[]{(8+1)^2+(10+2)^2}](https://tex.z-dn.net/?f=%7Cd%7C%3D%5Csqrt%5B%5D%7B%288%2B1%29%5E2%2B%2810%2B2%29%5E2%7D)
![=\sqrt[]{9^2+12^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B9%5E2%2B12%5E2%7D)
![=\sqrt[]{81+144}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B81%2B144%7D)
![=\sqrt[]{225}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B225%7D)
The distance is 15 units.
Answer:
160 units.
Step-by-step explanation:
In order to find the minimum cost, we need to find the vertex of the equation since it is the lowest point of the graph. To find the vertex, we use the following equation.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So we plug in and solve.
x = -b/2a
x = -(-80)/2(.25)
x = 80/.5
x = 160
Answer:
m = 0
Step-by-step explanation:
AB has a slope of y2 - y1 / x2 - x1 so -8-5/3-3 so -13/0 = undefined so it is a vertical line, so any line that is horizontal will be perpendicular to it, so horizontal lines have a zero slope
The circumference of a circle is always calculated by 2
R
So if R=2.5 m this circumference is 2*
*2.5 m
Which is 5
m (choice B)
Hope this helped!
Answer:
a=28 b=87
Step-by-step explanation:
a-10=18 a=10+18 a=28 b+16=103 b=103-16 b=87
