Answer:
n = 15
Step-by-step explanation:
For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.
If A is to run faster than B, 100n^2 must be smaller than 2^n.
Let's check from n = 1 to know the value of n that fits
n = 1
100(1)^2 > 2^1
100 > 2
n = 2
100(2)^2 > 2^2
400 > 4
n = 4
100(4)^2 > 2^4
1600 > 16
n = 8
100(8)^2 > 2^8
6400 > 2^8
n = 16
100(16)^2 < 2^16
25600 < 2^16
This implies that between n = 8 and 16, A starts to run faster than B
n = (8+16)/2 = 12
100(12)^2 > 2^12
14400 > 2^12
n = (12+16)/2 = 14
100(14)^2 > 2^14
19600 > 2^14
n = (14+16)/2
n = 15
100(15)^2 < 2^15
22500 < 2^15
At n= 15, A starts running faster than B
Answer:
y= 1.2x+1
Step-by-step explanation:
(0,1) and (-5,-5) are coordinates that you already know and are fs about. So you just see rise over run. 6/5 = 1.2 which is your slope. the y-int is 1 bc thats where it intersects. so your equation is y=1.2x+1
double check:
y = 1.2(-5) + 1
y = -6 + 1
y = -5
coordinates : (-5,-5)
Answer: May you show the angle we are supposed to solve? its a bit unclear. or can you explain the angle to us?
Step-by-step explanation:
(x–4) (3x^2 + 2)
i hope that helps with you’re expression
Answer:
The least common denominator would be 28.
Mutiply by 7 for 3/4.
Mutiply by 2 for 5/14.
3(7)/4(7)= 21/28, 5(2)/14(2)= 10/28
