Please help me with detail and also I need this by tomorrow. Please answer as soon as possible.

Find the percent of the area under the density curve where x is more than 3. <br>

Gekata [30.6K]

Answer:

The percent of the area under the density curve where $x$ is more that 3 is 25 %.

Step-by-step explanation:

Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:

$A = \frac{1}{2}\cdot (x_{f} - x_{o})\cdot (y_{f}-y_{o})$ (1)

Where:

$A$ - Area, in square units.

$x_{f} - x_{o}$ - Base of the triangle, in units.

$y_{f} - y_{o}$ - Height of the triangle, in units.

The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:

$x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%$

$x = 25\,\%$

The percent of the area under the density curve where $x$ is more that 3 is 25 %.

7 0

3 years ago

Can someone help me out with this one?

Juliette [100K]

I recommend u use the app called photomath. It works a lot.

8 0

3 years ago

Which is first X axis or Y axis?

Svetllana [295]

Answer:

You always do the X-axis first. Hope this helps! :)

<h3>CloutAnswers</h3>

5 0

3 years ago

Read 2 more answers

Write the polynomial in standard form -7x+10x^3-7x^2-x^8+15

kkurt [141]

Answer:

-x^8+10x^3-7x^2+7x+15

Step-by-step explanation:

-7x+10x^3-7x^2-x^8+15

Standard form is from highest power to lowest power of x

-x^8+10x^3-7x^2+7x+15

8 0

3 years ago

A random sample of 100 people was taken. Eighty-five of the people in the sample favored Candidate A. We are interested in deter

lbvjy [14]

Answer:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.85$ estimated proportion of people who favored candidate A

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.8.:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

8 0

2 years ago