To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.
161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857
Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.
The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
Answer: a.This is the average number of days the house stayed on the market before being sold for $150,000.
Step-by-step explanation:
Given: f(p) be the average number of days a house stays on the market before being sold for price p in $1,000s.
To find the meaning f(150),
here p= 150 which means f(150) is the average number of days a house stays on the market before being sold for price 150 in $1,000s.
And 150 in $ 1,000= $150,000
Therefore, f(150) is the average number of days a house stays on the market before being sold for price $150,000.
Answer: x=15
Step-by-step explanation: Let's solve your equation step-by-step.
x+
1
/2
(x−5)=20
Step 1: Simplify both sides of the equation.
x+
1
/2
(x−5)=20
x+(
1
/2
)(x)+(
1
/2
)(−5)=20(Distribute)
x+
1
/2
x+ −5
/2
=20
(x+
1
/2
x)+(
−5
/2
)=20(Combine Like Terms)
3
/2
x + −5
/2
=20
3
/2
x + −5
/2
=20
Step 2: Add 5/2 to both sides.
3
/2
x + −5
/2 + 5
/2
=20+
5
/2
3
/2
x= 45
/2
Step 3: Multiply both sides by 2/3.
(
2
/3
)*(
3
/2
x)=(
2
/3
)*(
45
/2
)
x=15
Adds 3 each time
first term is 5
an=a1+d(n-1)
d=common difference
a1=first term
an=5+3(n-1)
18th term
a18=5+3(18-1)
a18=5+3(17)
a18=5+51
a18=56
C is answer
