Answer: 0.4667
Step-by-step explanation:
According to 68–95–99.7 rule , About 99.7% of all data values lies with in 3 standard deviations from population mean ().
Here , margin of error = 3s , where s is standard deviation.
As per given , we have want our sample mean to estimate μ μ with an error of no more than 1.4 point in either direction.
If 99.7% of all samples give an within 1.4 , it means that
Divide boths ides by 3 , we get
Hence, So must have 0.4667 as standard deviation so that 99.7 % 99.7% of all samples give an within 1.4 point of μ .
Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
That answer your looking for is 80
Answer:
(1,4)
Step-by-step explanation:
if u substitute these numbers u can find out that these numbers make the solution.
hope this helps
It’s A 44-1) and if not then it’s b