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Greeley [361]
2 years ago
15

use the given circle. Find the length s to the nearest tenth A. 33.5 cm B. 8.4 cm C. 16.8 cm D. 5.3 cm​

Mathematics
1 answer:
Leokris [45]2 years ago
5 0

Answer:

16.8

Step-by-step explanation:

s = ∅ × r

= 2π/3 × 8

= 16/3 * π

= 16.75516

= 16.8

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A 10-foot ladder leans against a wall with its foot braced 3 feet from wallÍs base. How far up the wall does the ladder reach?
iren2701 [21]
The answer is √91 feet (which is the same as 9.54 feet).

Imagine this as a right triangle. A length of the foot is actually a hypotenuse (c). The distance from wall's base to the ladder foot is one of the sides of the triangle (let it be a).
So, using the Pythagorean theorem:
c² = a² + b²
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c = 10 feet
a = 3 feet
b = ?
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5 0
3 years ago
A plane flying over the ocean is on course to land on an aircraft carrier. The diagonal distance between the plane and the aircr
fomenos

Answer:

the plane's current height above the ocean is 3.42 miles

Step-by-step explanation:

Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.

What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.  

For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.

let a = diagonal distance = 10 miles

let the opposite angle to the diagonal distance be A = 90° (right angle)

let the vertical distance = b

let the opposite angle to the vertical distance be B = 20°

Sine rule states that    \frac{a}{sin(A)}  =  \frac{b}{sin(B)}

∴   \frac{10}{sin(90)}  =  \frac{b}{sin(20)}

b  =  sin(20)\frac{10}{sin(90)}

b  =  0.342*\frac{10}{1}

⇒ b = 3.42 miles

Therefore the plane's current height above the ocean is 3.42 miles

4 0
3 years ago
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