I have 4 questions (please help) IM BEGGING YOU i need help! please!!!!

1 answer:

6 0

1) 18h = 252
You divide each side by 18, so you can get "h" alone on a side, and its value on the other side of the equation.
(18h)/18 = 252/18
h = 14 (Answer C)

2) 31d = 186.
Same Thing, you divide each side by 31, so you can get "d" alone on a side, and its value on the other side of the equation.
(31d)/31 = 186/31
d= 6 (Answer B)

3) 55c = 385
Again, same thing, You divide each side by 55, so you can get "c" alone on a side, and its value on the other side of the equation.
(55c)/55 = 385/55
c = 7 (Answer B)

4) 50w = 1050
You divide each side by 50, so you can get "w" alone on a side, and its value on the other side of the equation.
(50w)/50 = 1050/50
w=21 (Answer A)

As you can notice, they all follow the same steps: dividing by the coefficient of the variable both sides, so you can the variable alone on the first side of the equation, and its value on the second side.

Hope this Helps! :)

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According to a survey, 29% of people carry at least 1 reusable water bottle. If 5 people are selected randomly, what is the prob

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Answer:

0.4 is the probability that at least 2 out of 5 will be carrying a reusable water bottle

Step-by-step explanation:

We are given the following information:

We treat people carrying at least 1 reusable water bottle as a success.

P(people carry at least 1 reusable water bottle) = 29% = 0.29

Then the number of people follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 5

We have to evaluate:

$P(x \geq 2) =1- P(x < 2) \\=1 - \binom{5}{0}(0.29)^0(1-0.29)^5 + \binom{5}{1}(0.29)^1(1-0.29)^4\\=1- 0.1804 - 0.3684\\= 0.4512\\\approc 0.4$

0.4 is the probability that at least 2 out of 5 will be carrying a reusable water bottle

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3 years ago

Someone help??????????????

irina1246 [14]

I: x-2y>=8
II:2x+y<=3

start by isolating y on a side

with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4

with II:
2x+y<=3
y<=-2x+3

now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4

y<=-2x+3
->
y=-2x+3

look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.