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Wewaii [24]
3 years ago
7

Simplify (use only positive exponents) : (3y^10)(2y^2)/8y^5

Mathematics
1 answer:
nadezda [96]3 years ago
5 0
When multiplying variables with exponents, all you have to do is to add the exponents and that’s the ‘product.’

So;

(3y^10)(2y^2) is equal to (3)(2)(y^10+2).

6y^12/8y^5


When dividing exponents, you do the opposite and subtract the exponents. And you divide the whole number by half.


6y^12/8y^5 = 3y^7/4

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What am I doing wrong
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The surface area, S, of a sphere of radius r feet is S = S(r) = 4πr^2. Find the instantaneous rate of change of the surface area
8090 [49]
Instantaneous rate of change = S'(r) = 8πr
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Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span>  is 64π
7 0
3 years ago
The sum of two consecutive integers is 65. what are the two integers? show steps please.
Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

\longmapsto\sf{2x=64}

Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0
2 years ago
The figure is made up of a square and a rectangle. Find the area of the shaded region.
Viefleur [7K]

Answer:

40 square metres

Step-by-step explanation:

The shaded region is of a triangle, whose area is denoted by: A = (1/2) * b * h, where b is the base and h is the height.

Since the left figure is a square with side lengths 10, we know that the height of the triangle is also 10 metres. The right figure is a rectangle with length 4. Since the total base length of the entire figure is 18 and the base of the square is 10, then the width of the rectangle is 18 - 10 = 8 metres.

This width is also the base of the triangle, so b = 8.

Now plug these values into the equation:

A = (1/2) * b * h

A = (1/2) * 8 * 10 = (1/2) * 80 = 40

The area is 40 square metres.

6 0
3 years ago
Read 2 more answers
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