the area of a square = length*length =3a*3a=9a^2
Answer:
$3
Step-by-step explanation:
23-17=6
6/2=3
To check:
6+17=23
Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
G(x) = 2x + 2
g(a + h) - g(a) = 2(a+h) + 2 - (2(a) + 2)
g(a + h) - g(a) = 2a + 2h + 2 - 2a - 2
g(a + h) - g(a) = 2h + 2 - 2
g(a + h) - g(a) = 2h
Your final answer is a. 2h.
