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Tju [1.3M]
3 years ago
9

-3x + 7y = -16 -9x + 5y = 16

Mathematics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

x = -4 y =-4

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Need help please thanks :)
luda_lava [24]

Answer:

800 ft, you should write ur own sentence tho

Step-by-step explanation:

520 - (-280) = 800

6 0
3 years ago
Combine any like terms in the expression. If there are no like terms rewrite the expression.
swat32

Answer:

0

Step-by-step explanation:

7jk + 3jk = 10jk

10jk - 4jk = 6jk

6jk - 6jk = 0jk

0jk = 0

4 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
2 years ago
Make the b the subject of b2 - 4ac = x
devlian [24]
Solve for b.
b^2= x+4ac
So b=sq root of x+4ac
7 0
3 years ago
Solve.
Citrus2011 [14]
The solution is (3,-1)

4 0
2 years ago
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