Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language)
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^
Answer: X = -2
Step-by-step explanation:
Answer:
13 sides
Step-by-step explanation:
1980 = (n − 2)×180 Formula for number of sides
n − 2 = 1980/180 Divide both sides by 180
n - 2 = 11
+ 2 + 2 Add 2 to both sides
n = 13
Answer:
1 19/24
Step-by-step explanation:
