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2 years ago

Hey I need help with this question thanks for people who can help me and have a good day could you include explanation

Mathematics

1 answer:

Aleks04 [339]2 years ago

5 0

Answer:

Step-by-step explanation:

<u>Formula</u>

$B = 25(\frac{M}{10} +\frac{3}{4} )$

Where M meters of granola makes B granola bars.

<u>Given:</u>

M = 2.5 meters

Now substitute that value in the formula and calculate.

$B=25(\frac{2.5}{10} +\frac{3}{4} )= 25(1) = 25$

Therefore, 2.5 meters of granola makes 25 granola bars.

B = 25

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Which is a greater slope 3 or -4

castortr0y [4]

Answer:

3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.

Step-by-step explanation:

3 is greater than -4, so strictly speaking, a slope of 3 is greater than a slope of -4.

On the other hand, the steepness of a line depends on the absolute value of the slope.

|3| = 3

|-4| = 4

Since 4 > 3, the line with slope -4 is steeper than the line with slope 3.

Answer: 3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.

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2 years ago

What is the factorization of the polynomial below? x^3 + 8x^2 + 17x + 10

faltersainse [42]

Answer:

This is your answer.

Step-by-step explanation:

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2 years ago

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Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

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2 years ago

What are the roots of the equation? x2−x−42=0 Enter your answers in the boxes.

Levart [38]

Answer:

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Step-by-step explanation:

x^2−x−42=0

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3 years ago

29/1000 as a percent

Sholpan [36]

2.9%

because you have to divide 29/1000 then move the decimal place

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2 years ago

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