Answer:
A. (4, 3, -1)
Step-by-step explanation:
The coefficient is the quantity before the variable.
Hope this helps mate. :)
Answer:
Explanatio1- To make 18 bags of snack mix, Sherry needs 4.5 cups of almonds.
As the original recipe is for 6 bags, and here Sherry wants to triple that amount. You have to multiply 1.5 x 3.
2- Sherry needs 6 cups of granola to make 12 bags of the snack mix.
If Sherry gets 6 bags using 3 cups of granola, she will get 12 by using 6 cups of granola.
3- If Sherry uses one cup of cranberries, she will need to use 2 cups of raisins.
As 1 cup of cranberries is the double of what the recipe states, Sherry should also double the amount of cups of raisins.
4- The recipe will make 2 bags of the snack mix if Sherry uses only one cup of granola.
As 1 cup of granola is a third of the amount detailed in the recipe for 6 bags, the amount of bags will also be reduced to a third. 6/3=2n:
Step-by-step explanation:
Answer:
Step-by-step explanation:
m and n are parallel and cut by a transversal
<u>Finding x</u>
- 8x + 12 + 2x + 18 = 180 (consecutive interior angles sum up to 180°)
- 10x + 30 = 180
- 10x = 150
- x = 15
<u>Finding y</u>
- 8x + 12 = 3y - 18 (vertical angles are equal)
- 8(15) + 12 = 3y - 18
- 132 = 3y - 18
- 150 = 3y
- y = 50
I think the rate is decreasing from:
(-infinity, ln9/3)
F is increasing if f '(x) = 4x^3<span> - 64x >0, so it is the same of x(x^2 -16)>0, implies x>0 or (x-4)(x+4)>0, so x> + or -4
the answer is </span><span>(-4 , 0) ∪ (4 , infinity)
</span>f is decreasing if f '(x) = 4x^3 - 64x <0, so it is the same of x(x^2 -16)<0, implies x<0 or (x-4)(x+4)<0, so x< + or -4
the answer is (- infinity, -4) ∪ (0 , 4)
<span>the local minimum and maximum
</span>f '(x) =0, impolies x=+ or -4, or x=0
or f'(o)=0, and f'(- 4)=f'(4)= 0,
M(-4, 0) or M(4, 0) or M(0,0)
<span>inflection points can be found by solving f '' (x)=12x^2 - 64 =0
</span>x=+ or - 4sqrt(3) / 3
so the inflection point is and M(- 4sqrt(3) / 3, f'' ( -4sqrt(3)) (smaller x value), and M(4sqrt(3) / 3, f'' (4sqrt(3)) (larger x value)
f is concave up if f ''>0
it means 12x^2 - 64>0, so the interval is (- infinity, -4sqrt(3) U (4sqrt(3), infinity)
f is concave down if f ''<0
it means 12x^2 - 64<0 so the interval is (-4sqrt(3)) U (4sqrt(3))
