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3 years ago

Are the numbers from the table -2, 0, 2, and 4 linear or nonlinear? how about -1, 0, 1, 2?

Mathematics

1 answer:

monitta3 years ago

5 0

Answer:

linear the first and the second

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1/2 greater than or less than 3/15

Colt1911 [192]

Greater
If we get common denominators
1/2=15/30
3/15=6/30
15>6 therefore 1/2>3/15

5 0

3 years ago

3.<br> Find the measure of each angle. If 34 degrees is given below.

Anettt [7]

Answer:

a. 34

b 146

c 146

d. 34

e 146

f 146

Step-by-step explanation:

4 0

3 years ago

An unbiased coin is tossed 15 times. In how many ways can the coin land tails either exactly 8 times orexactly 5 times?

Kitty [74]

Answer:

Probability to get tails exactly 8 times or exactly 5 times is 0.29

Step-by-step explanation:

No of ways the coins lands tails exactly 8 times

P(8) = 15C8 × $0.5^{8}$ × $0.5^{15-8}$

No of ways the coin lands tails exactly 5 times

P(5) = 15C5 × $0.5^{5}$ × $0.5^{15-5}$

Probability to get tails exactly 8 times or 5 times

P(8)+P(5) = 15C8 × $0.5^{15}$ + 15C5 × $0.5^{15}$

P = $0.5^{15}$ ( 15C8 + 15C5 )

P = $0.5^{15}$ ( ( $\frac{15!}{8!(15-8)!}$ ) + ( $\frac{15!}{5!(15-5)!}$ ) )

P = $0.5^{15}$ ( 6435 + 3003 )

P = $0.5^{15}$ ( 9438)

P = $0.5^{14}$ ( 4719)

P = $\frac{4719}{16384}$

P = 0.29

8 0

3 years ago

1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

$\csc \beta \tan \beta = \frac{1}{ \cos \beta } = \sec \beta$

Therefore,

$\sec \beta = ( \frac{7}{3} )( - \frac{3 \sqrt{10} }{20} ) = - \frac{7 \sqrt{10} }{20}$

$\csc y = \frac{1}{ \sin y} = - \frac{ \sqrt{6} }{2}$

$= > \sin y = - \frac{ \sqrt{6} }{3}$

Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

$\tan \beta = \frac{ \sin y}{ \cos y} =( - \frac{ \sqrt{6} }{3} )( - \frac{3}{ \sqrt{3} } ) = \sqrt{2}$

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

$\sin x = \sqrt{1 - \cos ^{2} x} = \sqrt{ \frac{11}{6} }$

Solving for tan x:

$\tan x = \frac{ \sin x}{ \cos x} = (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) = \frac{ \sqrt{66} }{5}$

5 0

3 years ago

The Florida Everglades welcomes about 2 times 10 to the 3 power visitors per day . Based on this about how many visitors come to

Snezhnost [94]

About 8,000 people visit the Florida Everglades each week

6 0

3 years ago

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