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3 years ago

What's the equation of a line that passes through (-4,-7) and (4,-1)

Mathematics

2 answers:

Alborosie3 years ago

5 0

What's the equation of a line that passes through (-4,-7) and (4,-1)

Answer:

y=-x+3

harina [27]3 years ago

3 0

Answer:

y = 3/4x - 4

Step-by-step explanation:

Slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (-1 - (-7)) / (4 - (-4))

= 6 / 8

= 3/4

y-intercept:

y = mx + b

use the slope above and anyone of the given points to find b. Let's use (4, -1)

(-1) = 3/4(4) + b

-1 = 12/4 + b

- 1 = 3 + b

b = -4

Equation of a line:

y = mx + b

use the m and b from above to form the equation of a line.

y = 3/4x - 4

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EleoNora [17]

We want to find 9.5% of $50.

First put 9.5% in decimal form. 9.5% = 0.095.

Then multiply 0.095 by 50. 50 * 0.095 = $4.75 fee

The money Kennedy will recieve is going to be 50 dollars minus the $4.75 fee.

50 - 4.75 = $45.25 with the fee subtracted

4 0

3 years ago

A glacier receded 4 feet a day for a period of 25 days how much shorter was the glacier at the end of the period

KonstantinChe [14]

4*25=100

The glacier was 100 feet shorter than it was originally by the end of the 25 day period.

Hope this helps :)

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2 years ago

Consider the function represented by the equation x - y = 3. What is the equation written in function notation, with x

Svet_ta [14]

Independent Variable Y-3(x)

5 0

2 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

What is 8/15 plus 2/5 equal to

anastassius [24]

We have to add 8/15 to 2/5.

To add two fractions we have to make them have the same denominator, so we have to convert 2/5 to have a denominator of 15. To do this, we have to multiply 2/5 by 3 and then we can add the fractions:

$\begin{gathered} \frac{8}{15}+\frac{2}{5} \\ \frac{8}{15}+\frac{2}{5}\cdot\frac{3}{3} \\ \frac{8}{15}+\frac{6}{15} \\ \frac{14}{15} \end{gathered}$

Answer: 14/15

5 0

10 months ago