What's the equation of a line that passes through (-4,-7) and (4,-1)

Mathematics

2 answers:

Alborosie3 years ago

5 0

What's the equation of a line that passes through (-4,-7) and (4,-1)

Answer:

y=-x+3

harina [27]3 years ago

3 0

Answer:

y = 3/4x - 4

Step-by-step explanation:

Slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (-1 - (-7)) / (4 - (-4))

= 6 / 8

= 3/4

y-intercept:

y = mx + b

use the slope above and anyone of the given points to find b. Let's use (4, -1)

(-1) = 3/4(4) + b

-1 = 12/4 + b

- 1 = 3 + b

b = -4

Equation of a line:

y = mx + b

use the m and b from above to form the equation of a line.

y = 3/4x - 4

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What are the first and last terms of this geometric series

11Alexandr11 [23.1K]

ANSWER

E. 10 and 640

EXPLANATION

The given series is

$\sum_{i=1}^45 \times 2^{2i-1}$

To find the first term of the series we substitute i=1 to get,

$a_1 = 5 \times {2}^{2 \times 1 - 1}$

$a_1 = 5 \times {2}^{ 1} = 10$

For the last term of the series, we substitute i=4 to obtain,

$a_4 = 5 \times {2}^{2 \times 4 - 1}$

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This implies that,

$a_4 = 5 \times 128 = 640$

Therefore the correct answer is E

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Step-by-step explanation:

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3 years ago

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erastovalidia [21]

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