What's the equation of a line that passes through (-4,-7) and (4,-1)
2 answers:
What's the equation of a line that passes through (-4,-7) and (4,-1)
Answer:
y=-x+3
Answer:
y = 3/4x - 4
Step-by-step explanation:
Slope:
m = (y₂ - y₁) / (x₂ - x₁)
= (-1 - (-7)) / (4 - (-4))
= 6 / 8
= 3/4
y-intercept:
y = mx + b
use the slope above and anyone of the given points to find b. Let's use (4, -1)
(-1) = 3/4(4) + b
-1 = 12/4 + b
- 1 = 3 + b
b = -4
Equation of a line:
y = mx + b
use the m and b from above to form the equation of a line.
y = 3/4x - 4
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