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Verdich [7]
3 years ago
12

1/R = 1/A + 1/B assuming that all denominators are non-zero solve for B

Mathematics
1 answer:
Rashid [163]3 years ago
7 0

Answer:

1/B = 1/R - 1/A

B/R - B/A = 1

B - BR/A = 1

B = 1 + BR/A

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Vinvika [58]
Ur answer Should be 18f
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3 years ago
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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that a = 10400, b = 15400

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0
3 years ago
A person invests 3000 dollars in a bank. The bank pays 6.75% interest compounded
stich3 [128]

Answer:

12.1 years

Step-by-step explanation:

We are given that

Principal amount, P=$3000

Rate of interest, r=6.75%  semi-annually

Amount, A=$6700

We know that

When r pays semi-annually

A=P(1+\frac{r}{n\times 100})^{nt}

Where n=2

Using the formula

6700=3000(1+\frac{6.75}{200})^{2t}

\frac{6700}{3000}=(1..03375)^{2t}

2.233=(1.03375)^{2t}

Taking ln on both sides we get

ln(2.233)=2t ln(1.03375)

2t=\frac{ln(2.233)}{ln(1.03375)}

t=\frac{1}{2}\times \frac{ln(2.233)}{ln(1.03375)}

t=12.1 years

8 0
3 years ago
Calculate the interest rate when the principal is $300 and interest earned is $40 after 3
stich3 [128]

Answer:

4.4%

Step-by-step explanation:

solution:

principal (p) = $300

time(t) = 3 years

interest (I ) =$40

rate (r) = ?

we know that,

I = (PTR)/100*

OR, 40 = (300 *3 * R)/100

or, 40 = (900R)/100

or, 40 = 9R

or, 40/9 = R

or, R = 4.4%

Rate(r) =4.4%

3 0
3 years ago
If five kids sit on a d and one has an orgasm how many are still going
Ierofanga [76]

Answer:

jesus...you're twisted anyway 69 :)

Step-by-step explanation:

4 0
3 years ago
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