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Anna11 [10]
3 years ago
10

In 2010, the population of a city was 180,000. From 2010 to 2015, the population grew by 7%. From 2015 to 2020, it fell by 4%. H

ow much did the population grow from 2010 to 2015, to the nearest 100 people?
Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0

Answer:

9800

Step-by-step explanation:

Scrat [10]3 years ago
3 0

Answer:

I. Exponential Growth. (1 ) t y C r. = +. Final. Amount. Initial. Amount. Rate of ... value increases by 7% each year. ... Step 1 Write the exponential growth function for this ... nearest hundredth. ... The population after 7 years will be approximately 38,783 people. ... Cesium-137 left from a 100 milligram sample after 180 year

Step-by-step explanation:

i think  its right  if not have  a  great  day

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GREYUIT [131]
The answer to this question is going to be letter B
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3 years ago
a plumber charges $52.50 per hour plus a $75.00 service charge your father's firm hires him to fix some leaky pipes find the tot
aleksley [76]

(4.5 x 52.5) + 75 = 311.25

7 0
4 years ago
Read 2 more answers
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
Wiley wants to make as many snack
Ghella [55]

Answer:

Wiley can make 10 snack packs.

Step-by-step explanation:

Assuming that you can't put a fraction of one item in a snack pack and yoou must use all the items, Each pack must contain a integer number of items. The smallest possible way is for each snack pack to contain 3 slices of cheese and 4 crackers. This results in a total of 10 snack packs.

6 0
4 years ago
What is the answer????????? help
fenix001 [56]
80


adding up the numbers 30,20,5,25

maybe im wrong but i hope it helps...
8 0
3 years ago
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