Usual distance michiko runs= d miles
Time=t
normal speed= r₀
speed today= r₁
According to the question,
r₀= d/t
r₁= d+9/t+70.
Answer:
- train: 40 kph
- plane: 140 kph
Step-by-step explanation:
Let t represent the speed of the train in km/h. Then 4t-20 is the speed of the plane. Travel times are the same, so we can use the formula ...
time = distance/speed
and equate the travel times.
110/t = 385/(4t-20)
Cross multiplying gives ...
110(4t -20) = 385t
440t -2200 = 385t . . . . . eliminate parentheses
55t -2200 = 0 . . . . . . . . . subtract 385t
t -40 = 0 . . . . . . . . . divide by 55
t = 40 . . . . . . . . . . . add 40; train's speed is 40 kph
4t -20 = 140 . . . . . . find plane's speed; 140 kph
The train's speed is 40 km/h; the plane's speed is 140 km/h.
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<em>Check</em>
Train's travel time = 110 km/(40 km/h) = 2.75 h.
Plane's travel time = 385 km/(140 km/h) = 2.75 h.
The answer is 8/10. If you multiply it by two (top and bottom) then you will get 8/10.
Answer: Hello mate!
our equation is 18√5−12√5 and we want to simplify it.
Simplification is triyng to "eliminate" all the roots (if possible). In our equation we have a square root of 5, wich is a problem, but let's se wat we can do:
18√5−12√5
= (18 - 12)√5
= 6√5
and we can not simplify furthermore, because the √5 cant be simplifyed.
