(2x^2+3x^3-16-8x) / (x-2)
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Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c = = 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
