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KengaRu [80]
3 years ago
13

Can someone please help me

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0
I think it is c. but i'm not sure
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Find the value of x in the figure.
horsena [70]

Answer:

x = 35

Step-by-step explanation:

First count how many interior angles we have here.

There are 6 interior angles.

so we then can determine the interior sum of the angles here.

Inside angle sum = 180*(6 - 2)  degrees  = 180*4 = 720 degrees

so

(4x - 5)+(4x - 3) + 118 +(3x+6) + (3x-3) + 117 = 720 degrees

8x - 8 + 118 + 6x + 3 + 117 = 720 degrees

14x -8 + 118 + 120 = 720 degrees

14x + 230 = 720

14x = 720 - 230

14x = 490

x = 35

7 0
3 years ago
If f(x)=7-3x and g(x)=3x-7, what is the value of f(1)-g(1)?
postnew [5]
Substitute 1 for x in each of your equations.

f(x)=7-3x
which is
f(1)=7-3(1)
=3
Do the same for g(x)
g(x)=3x-7
which is
g(1)=3(1)-7
=-4

Then subtract g(x) from f(x):
3-(-4)
=7

:)

6 0
3 years ago
PLEASE HELP ME I DON T UNDERSTAND IF YOU PLEASE COULD HELP ME I WOULD GREATLY APPRECIATE IT REALLY THANK YOU
butalik [34]

Find the length of one side.

V = s^3

s = cube root of V

V = 729

s = cube root 729

s = 9

Put this into your calculator as 729^0.333333333

It should bring back 9 or 8.999999 something which means 9.

Net

The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?

Area of one face = s^2

s = 9

Area of one face = 9*9

Area of one face = 81

So when you draw this, each face should be labeled with 81.

It should have it's units (ft^2) if your marker is picky.

Part C

There are 6 sides.

1 side has an area of 81 ft^2

6 sides have an area of 6*81 = 486 ft^2

5 0
3 years ago
Can a right triangle be formed using these squares
Ilya [14]

Yes. The two smaller squares have a sum of 169 which is the value of the larger square.

a^2 + b^2 = c^2

25 + 144 = 169

It can be done. Notice the figure below shows you how to arrange the squares to give the answer of a^2 + b^2 = c^2

7 0
3 years ago
Find the domain of the graphed function. Help me please);
pogonyaev

The correct answer is B. -4<x<2.

This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.

8 0
3 years ago
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