For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Step-by-step explanation:
5×9×12=540
6×9×12÷2=324
324+540=864
5
6x5 is 30
I’m pretty sure that’s the answer hope it helps
Answer:
The slope is 2
The y-intercept is 3
The equation is y = 2x +3
Step-by-step explanation:
The equation goes up 2 squares and over 1 square. 2/1 = 2
For y-intercept, look at the y-axis
The equation is supposed to be written as y = mx + b
m being the slope and b being the y-intercept.
