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3 years ago

F(x) = 4x + 5 what is the value of f(-3)

Mathematics

1 answer:

myrzilka [38]3 years ago

7 0

Answer:

-7

Step-by-step explanation:

step 1,

put -3 into the function

step 2,

4(-3) + 5 = -7

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The product of 5 and cube of x increased by the difference of 6 and x3?

Vinil7 [7]

$The\ ptoduct\ of\ 5\ and\ cube\ of\ x:5\times x^3=5x^3\\\\The\ difference\ of\ 6\ and\ x^3:6-x^3\\\\Answer:\boxed{5x^3+(6-x^3)=4x^3+6}$

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3 years ago

Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at

Dafna1 [17]

Answer:

$\huge\boxed{ \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

conic sections
PEMDAS

<h3>tips and formulas:</h3>

$\sf hyperbola \:equation : \\ \sf \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1$
vertices of hyperbola:(±a,0) and (0,±b) if reversed
$\sf \: asymptotes : \\ y = \pm\frac{b}{a} x$

<h3>given:</h3>

vertices: (0,±10)
the hyperbola equation is inversed since the vertices is (0,±10)
asymptotes: $\pm \frac{5}{6}x$

<h3>let's solve:</h3>

the asymptotes are in simplest and we know b is ±10

according to the question

$y = \sf \frac{5 \times 2}{6 \times 2} x \\ y = \frac{10}{12} x$

therefore we got

a=12
b=10

note: the equation will be inversed

let's create the equation:

$\sf substitute \: the \: value \: of \: a \: and \: b : \\ \sf \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1$

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

For question 38

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