Which one is right and how do I solve with out showing my work

Mathematics

1 answer:

hram777 [196]3 years ago

4 0

To simplify 12/18, you can see that the greatest common factor is 6 (6 × 2 = 12, 3 × 6 = 18), and so you can divide by 6 to get D. 2/3 as your answer.
I'm pretty sure you could just select the answer to not show your working :)

I hope this helps!

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(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)

nalin [4]

First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx

7 0

3 years ago

Read 2 more answers

A bicycle rider increases his speed from 5 m/s to 15 m/s in 10 seconds

valentina_108 [34]

To find the acceleration of the bicycle rider, we are going to use the acceleration formula: $a= \frac{v_{f}-v_{i}}{t}$
where
$a$ is the acceleration
$v_{i}$ is the initial speed
$v_{f}$ is the final speed
$t$ is the time

We know from our problem that increases his speed from 5 m/s to 15 m/s in 10 seconds, so his initial speed is 5 m/s and his final speed is 15 m/s; therefore, $v_{i}=5$ , $v_{f}=15$ , and $t=10$ . Lets replace those values in our formula:
$a= \frac{v_{f}-v_{i}}{t}$
$a= \frac{15-5}{10}$
$a= \frac{10}{10}$
$a=1$

We can conclude that the acceleration of the bicycle rider 1 m/s^2

4 0

3 years ago

Please help I need work shown!!

likoan [24]

3x-11=2x+11

x=22

3x-11=55

2x+11=55

55+55+2y=180

2y=70

y=35

x=22 , y=35