Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
![P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05](https://tex.z-dn.net/?f=P%28C%29%20%3D%201%20-%20%5BP%28A%29%20%2B%20P%28B%29%20%2B%20P%28N%29%5D%5C%5C%3D%201%20-%20%5B0.26%20%2B%200.65%20%2B%200.04%5D%5C%5C%3D%201%20-%200.95%5C%5C%3D%200.05)
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Answer:
5 ^15
Step-by-step explanation:
(5 ^3)^5 =5 ^(3×5)=5 ^15
Given function:
f(x) = 2 - 5x
Table;
x f(x)
-2 12
-1 7
0 2
1 -3
2 -8
The function is f(x) = 2 -5x
For; x = -2; f(x) = 2 - 5(-2) = 12
f(x) = 2 - 5(-1) = 7
f(x) = 2 - 5(0) = 2
f(x) = 2 - 5(1) = -3
f(x) = 2 - 5(2) = -8
Answer:
Step-by-step explanation:
770