Answer:
AC = 8 cm,
AD = 3 cm and ∠ACB = ∠CDA
From figure,
∠CDA = 90°
∴ ∠ACB = ∠CDA = 90°
In right angled ∆ADC,
AC2 = AD2 + CD2
⇒ (8)2 = (3)2 + (CD)2
CD2 = 64 – 9 = 55
⇒ CD = √55 cm
In ∆CDB and ADC.
∠BDC = ∠AD [each 90°]
∠DBC = ∠DCA [each equal to 90°-∠A]
∴ ∠CDB ∼ ∆ADC
Then,
There will be seven spaces between the 1st and the 8th post.
The distance between posts is 20 meters
The distance between the 1st and the 8th post is 20×7 = 140 metres
Answer:
A
Step-by-step explanation:
Answer:
x = 6
Step-by-step explanation:
When 2 chords of a circle intersect then the product of the parts of one is equal to the product of the parts of the other, that is
2x = 3 × 4, that is
2x = 12 ( divide both sides by 2 )
x = 6
Step-by-step explanation:
m<C = 90°
According to the laws of cosine,
c²= a²+b²-2ab. cos(C)
c²=a²+b²-2ab.cos(90°)
c²=a²+b²-2ab.0 { cos(90°)= 0}
c²=a²+b²
a²=c²-b²