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Dennis_Churaev [7]
2 years ago
8

HELP! 9 is what percent of 100 (need to show how I got my answer)

Mathematics
2 answers:
exis [7]2 years ago
6 0

Answer:

9%

Step-by-step explanation:

We can start by changing this number to a fraction.

\frac{9}{100}

We know that 100 is a whole percentage

Therfore, we would get 9%

faltersainse [42]2 years ago
4 0
The answer is 90% or 9 percent
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Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
3 years ago
What are the coordinates?
Yuki888 [10]

Answer: 2

Step-by-step explanation: (2x-4)

4 0
3 years ago
Show your work please help me with my homework thank you
AVprozaik [17]
Part. %
------ = -------
Whole 100

816. X
------- = ------
850. 100

850x=81600
-------- ---------
850. 850

X=96

96% of seats were sold
3 0
3 years ago
The expression 3 × n can be written without the multiplication sign as 3n. For each expression in parts (a)–(c), Use n = 1, 2, 3
baherus [9]
You can because you already know the number is 3 and the blank number is n
7 0
3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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