Algebra 2 Quadratics. Maximum Height of h(t) = -16t + 96t(with steps if possible)
1 answer:
Answer:
max. height = 240
Step-by-step explanation:
Function should be h(t ) = - 16t² + 96t
find the zeros by solving h(t) = 0
- 16t² + 96t = 0 ( take out common factor - 16t )
- 16t(t - 6) = 0
equate each factor to zero and solve for t
- 16t = 0 ⇒ t = 0
t - 6 = 0 ⇒ t = 6
the maximum vertex is at the midpoint of the zeros
t = = 3
h(3) = (- 16 × 3) + (96 × 3) = - 48 + 288 = 240 ← max. height
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