Question

Algebra 2 Quadratics. Maximum Height of h(t) = -16t + 96t(with steps if possible)

Answer 1

Answer:

max. height = 240

Step-by-step explanation:

Function should be h(t ) = - 16t² + 96t

find the zeros by solving h(t) = 0

- 16t² + 96t = 0 ( take out common factor - 16t )

- 16t(t - 6) = 0

equate each factor to zero and solve for t

- 16t = 0 ⇒ t = 0

t - 6 = 0 ⇒ t = 6

the maximum vertex is at the midpoint of the zeros

t = $\frac{0+6}{2}$ = 3

h(3) = (- 16 × 3) + (96 × 3) = - 48 + 288 = 240 ← max. height