(HELP ITS A EZ MULTIPLE CHOICE ILL GIVE BRAINLY!!)
1 answer:
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Answer:
<em>The answer is</em> <em>{-(5)
(36)×
-(180)</em>
Step-by-step explanation:
A polynomial with rational coefficients has roots 5 and -6i (There i is the
imaginary number not variable )
As we knew that imaginary no comes in pair . This means that if -6i is
one root then the other root will be 6i
So if we assume the lowest polynomial that is possible is given as
{-(sum of all roots)
+(roots taken two at a time)
-(product of all roots)
{-(5+6i+(-6i))
+(5×6i +5×(-6i) +6i×(-6i))
-(5×6i×(-6i))
= -1
<em>{-(5)
(36)×
-(180)</em>
<em> </em>The <u>general case</u> we assume that the three previous roots and rest roots
a4,a5,a6 ...............an
-(sum of all roots)×
+(roots taken two at a
time) ×- .......................................... (product of all roots)
Answer:
<em>y = - </em><em> cos ( </em>
<em> x ) , y = cos ( 3x ) + 2 </em>
Step-by-step explanation:
<u><em>Image 1.</em></u>
The graph is reflection of cosine over x-axis and max is 3.5 ⇒ A = -
Period is ( 4 π ) ⇒ B =
There are no horizontal and vertical shifts ⇒ C = D = 0
<em>y = - </em><em> cos ( </em>
<em> x )</em>
<u><em>Image 3.</em></u>
The graph of cosine shifted 2 units up only ⇒ D = 2 , C = 0
Period of the given function is ⇒ B = 3
<em>y = cos ( 3x ) + 2</em>
