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2 years ago

Find the percent of change when the price of a radio changes from $40.00 to $44.00.

Mathematics

1 answer:

HACTEHA [7]2 years ago

7 0

1) 10%
2)12%
3)20%
4)8%
5)50%

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HELP QUICK PLS!!!

Tomtit [17]

Answer:

Step-by-step explanation:

The lateral surface area is given by pi*r*l, we can use trigonometry to find l. 8*sqrt(3)/l=sin(60), l=16 and r is given by tan(60)=8*sqrt(3)/r, r=8. The lateral surface area is 16*8*pi=128*pi

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2 years ago

Taila is older than both her brother Henry and Frank.

S_A_V [24]

Answer:

Trying to get 24

Henry being 1 more than twice Frank age

Frank 3

Henry 7

Taila 14

3 *2=6+1=7*2=14

Step-by-step explanation:

4 0

2 years ago

How do you do 137 ÷ 7 in a area model

aliya0001 [1]

Hey,

If you were to divide 137/7 it would be it would be 19 or if you wont a decimal it would be 19.5

I Hoped that Helped

8 0

2 years ago

Read 2 more answers

An 80% confidence interval is (150, 170). What is the margin of error?

Viefleur [7K]

Answer:

Step-by-step explanation:

it is what it is

5 0

2 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

2 years ago