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jeka57 [31]
3 years ago
6

Ross is building a model of a square pyramid for a class project. The side length of the square base is 18 inches and the slant

height of the pyramid is 19 inches. What is the surface area of the model pyramid?
A. 666 in.2

B. 684 in.2

C. 1008 in.2

D. 495 in.2
Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Surface area of a square pyramid

= area of the base + 4 times area of one of the slanted faces

Area of the base = side length * side length = 18*18 = 324

Area of one slanted face = (1/2) * side length * slant height = 1/2*18*19 = 171

Surface area = 324 + 4 * 171

= 1008 in.2


ans is C


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Inga [223]

Answer:

g(x) = \frac{x+3}{x-3}

Step-by-step explanation:

From the picture attached,

Given function is,

f(x) = x + 1

We have to find the value of g(x) if the composite function has been given as,

f[g(x)] = g(x) + 1 = \frac{2x}{(x-3)}

g(x) = \frac{2x}{(x-3)}-1

      = \frac{2x-(x-3)}{(x-3)}

      = \frac{(x+3)}{(x-3)}

Therefore, g(x) = \frac{x+3}{x-3} will be the answer.

5 0
3 years ago
Make r the subject of the formula in I=E/R+r​
allochka39001 [22]

Step-by-step explanation:

I =  \frac{E }{ R}  + r

I  -  \frac{ E }{ R}  = r

\frac{I R -E  }{ R}  = r

HOPE IT HELPS Y

8 0
2 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
4 years ago
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Answer:

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