I believe (a+b)^5 would be the answer
Answer:
The method would use to prove that the two Δs ≅ is AAS ⇒ D
Step-by-step explanation:
Let us revise the cases of congruence:
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse and leg of the 1st right Δ ≅ hypotenuse and leg of the 2nd right Δ
In the given figure
∵ The two triangles have an angle of measure 30°
∵ The two triangles have an angle of measure 70°
∵ The two triangles have a side of length 10
∴ The two triangles have two equal angles and one equal side
→ By using rule 4 above
∴ The two triangles are congruent by the AAS rule
∴ The method would use to prove that the two Δs ≅ is AAS
Answer:
.05
Step-by-step explanation: .5 would be 50%
I assume 60 is the circumference of the circle.
if you sketch the graph, you will see that the radius from the center to the base, half the base, and the line segment form the center to one of the bottom vertex form a 30-60-90 degree triangle, the shortest leg is the radius of the circle, r.
the longer leg is √3r, and the hypotenuse is 2r.
the base of the triangle is 2√3r.
find r: 2πr=60, r=60/2π
2√3r=2√3*60/(2π)=60√3/π=33
The domain 2 would be plugged in as f (2)=2x+1 which equals 5
