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fiasKO [112]
2 years ago
6

CAN SOMEONE PLEASE HELP ME

Mathematics
2 answers:
Natalka [10]2 years ago
6 0
Ima say supplementary
solong [7]2 years ago
6 0
Corresponding angles are angles that the transversal line cuts across two straight lines and are congruent
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Applying Math<br> 8. Solve the equation to<br> show how/= becomes<br> R= Show your work.
Simora [160]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Point x is at 2/3 on number line. On the same number line point y is the same distance from 0 as point x but has a numberator of
Yanka [14]

Answer:  The answer is 12.

Step-by-step explanation: Given that a point 'x' is lying at \dfrac{2}{3} on the number line. Another point 'y' is also lying at the same distance from 0 but has a numerator of 8. We are to find the denominator of 'y'.

Since 'x' is lying at \dfrac{2}{3} on the number line so its distance from 0 will be

d_x=\dfrac{2}{3}-0=\dfrac{2}{3}.

Let the denominator of 'y' be p, then its distance from 0 will be

d_y=\dfrac{8}{p}-0=\dfrac{8}{p}.

According to the given information, we must have

d_x=d_y\\\\\\\Rightarrow \dfrac{2}{3}=\dfrac{8}{p}\\\\\\\Rightarrow p=\dfrac{8\times 3}{2}=12.

Thus, the denominator will be 12.

4 0
3 years ago
Marla swims twice a week. her equipment cost her $32.85 and she has a membership to the pool for $35 plus #3.50 per visit. she c
evablogger [386]
Around $634.85 per year

Because:

$32.85+$35(12 months)+$3.5(52 weeks in a year)= Total cost per year
                   $420                       $182

        $32.85 + $420 + $182 = $634.85 per year
3 0
3 years ago
Consider the function f(x)=8-3x^2. Find the value of f(x) when x=3 and select the correct answer below.
masya89 [10]
Yoooo the answer is A, -19. hope this helps, have an amazing day :)
3 0
3 years ago
Read 2 more answers
Calc 3 iiiiiiiiiiiiiiiiiiiiiiiiiiii
Lilit [14]

Take the Laplace transform of both sides:

L[y'' - 4y' + 8y] = L[δ(t - 1)]

I'll denote the Laplace transform of y = y(t) by Y = Y(s). Solve for Y :

(s²Y - s y(0) - y'(0)) - 4 (sY - y(0)) + 8Y = exp(-s) L[δ(t)]

s²Y - 4sY + 8Y = exp(-s)

(s² - 4s + 8) Y = exp(-s)

Y = exp(-s) / (s² - 4s + 8)

and complete the square in the denominator,

Y = exp(-s) / ((s - 2)^2 + 4)

Recall that

L⁻¹[F(s - c)] = exp(ct) f(t)

In order to apply this property, we multiply Y by exp(2)/exp(2), so that

Y = exp(-2) • exp(-s) exp(2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-s + 2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-(s - 2)) / ((s - 2)² + 4)

Then taking the inverse transform, we have

L⁻¹[Y] = exp(-2) L⁻¹[exp(-(s - 2)) / ((s - 2)² + 4)]

L⁻¹[Y] = exp(-2) exp(2t) L⁻¹[exp(-s) / (s² + 4)]

L⁻¹[Y] = exp(2t - 2) L⁻¹[exp(-s) / (s² + 4)]

Next, we recall another property,

L⁻¹[exp(-cs) F(s)] = u(t - c) f(t - c)

where F is the Laplace transform of f, and u(t) is the unit step function

u(t) = \begin{cases}1 & \text{if }t \ge 0 \\ 0 & \text{if }t < 0\end{cases}

To apply this property, we first identify c = 1 and F(s) = 1/(s² + 4), whose inverse transform is

L⁻¹[F(s)] = 1/2 L⁻¹[2/(s² + 2²)] = 1/2 sin(2t)

Then we find

L⁻¹[Y] = exp(2t - 2) u(t - 1) • 1/2 sin(2 (t - 1))

and so we end up with

y = 1/2 exp(2t - 2) u(t - 1) sin(2t - 2)

7 0
2 years ago
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