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2 years ago

When x = 1/2, what is the value of 8x-3/x?

Mathematics

1 answer:

sp2606 [1]2 years ago

4 0

Answer:

Step-by-step explanation:

Putting value of x = 1/2 in the equation

8x - 3/x

8(1/2) - 3(1/2)

= 4 - 3/2

= 2.5 or 5/2

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What is the area of the following circle?

Marysya12 [62]

Answer:

Area = pi X r^2 = pi x (1)^2 = 3.14 x 1 = 3.14

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

5c squared- d squared+3/2c - 4d...c= -1. d= -4

riadik2000 [5.3K]

For this case we have the following expression:

$5c ^ 2-d ^ 2 + \frac {3} {2} c-4d$

We must find the value of the expression when:

$c = -1\\d = -4$

Substituting we have:

$5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}$

Finally, the value of the expression is:

$\frac {7} {2}$

ANswer:

$\frac {7} {2}$

5 0

3 years ago

Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for <em>area</em> of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$