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3 years ago

When x = 1/2, what is the value of 8x-3/x?

Mathematics

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

Step-by-step explanation:

Putting value of x = 1/2 in the equation

8x - 3/x

8(1/2) - 3(1/2)

= 4 - 3/2

= 2.5 or 5/2

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System equations -2x-6y=-16

aalyn [17]

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3 years ago

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Which 2 teams scored a total of 100 points, red has 29 points, yellow has 38 points, Green has 41 points, blue has 76 points ora

Bess [88]

Answer:

Blue and Black

Step-by-step explanation:

hi! i think you're asking which of the 2 teams' points added together equal 100. if so, it would be blue and black because 76 + 24 = 100.

broken down: 70 + 20 = 90, 6 + 4 = 10, 90 + 10 = 100 :)

hope i understood this right!

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3 years ago

What is the unit rate for 220$ to 13ft

Firlakuza [10]

Answer:

Total Rate= 220$ and length = 13 ft

13/220$

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3 years ago

There are 52 potato chips in a 10 oz bag. Write and solve a porportion that you can use to find the number of chips in a 4 oz ba

natima [27]

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3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

$n = 345$

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

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3 years ago